例如传入时间字符:1809300000,1810050000
补齐时候的效果:1809300000,1810010000,1810020000,1810030000,1810040000,1810050000
sql语句如下:
SELECT to_char (startdate + LEVEL - 1,'yyMMddHH24mi') STATTIME
FROM (SELECT to_date('1810050000','yyMMddHH24mi') enddate, to_date('1809300000','yyMMddHH24mi') startdate
FROM dual)
CONNECT BY LEVEL <=floor(enddate-startdate+1)
效果如下: