CSE 105 - Reductions

subset inclusion doesn't determine difficulty!

ATM reduces to HALTTM = given a genie for problem X, we could decide problem Y

ATM is a subset of HALTTM

Statement: Σ* reduces to ATM -> Given a decider of ATM, I can build a decider for Σ* -> true

Σ* is decidable: we can build a TM that accepts all possible strings.

A is mapping reducible to B -> there is a computable function f such that for all strings x in Σ*

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转载自www.cnblogs.com/yxcindy/p/9998877.html
cse
105
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