27-remove-element

题目描述：

Your function should return length = 2, with the first two elements of nums being 2.

It doesn't matter what you leave beyond the returned length.

Example 2:

Given nums = [0,1,2,2,3,0,4,2], val = 2,

Your function should return length = 5, with the first five elements of nums containing 0, 1, 3, 0, and 4.

Note that the order of those five elements can be arbitrary.

It doesn't matter what values are set beyond the returned length.

Clarification:

Confused why the returned value is an integer but your answer is an array?

Note that the input array is passed in by reference, which means modification to the input array will be known to the caller as well.

Internally you can think of this:

// nums is passed in by reference. (i.e., without making a copy)
int len = removeElement(nums, val);

// any modification to nums in your function would be known by the caller.
// using the length returned by your function, it prints the first len elements.
for (int i = 0; i < len; i++) {
    print(nums[i]);
}

代码解答：

package com.jack.algorithm;

/**
 * create by jack 2018/11/5
 *
 * @author jack
 * @date: 2018/11/5 21:32
 * @Description:
 * 求去掉指定元素以后，新数组的长度
 */
public class RemoveElement {


    /**
     * 题目描述：
     * https://leetcode.com/problems/remove-element/
     * @param nums
     * @param val
     * @return
     */
    public static int removeElement(int[] nums, int val) {
        if (nums.length == 0) {
            return 0;
        }
        int i=0;
        for (int j=0;j<nums.length;j++) {
            if (nums[j] != val) {
                nums[i] = nums[j];
                i++;
            }
        }
        return i;
    }

    public static void main(String[] args) {
        //int[] nums = new int[]{3,2,2,3};
        //int[] nums = new int[]{3,2,2,3};
        int[] nums = new int[]{0,1,2,2,3,0,4,2};
        //int[] nums = new int[]{0,1,2,2,3,0,4,2};
        int v = 2;
        int length =removeElement(nums,v);
        System.out.println("length="+length);
    }
}

源码地址：

源码