C19

输入10个数，统计并输出其中正数，负数和零的个数

#include<stdio.h>
int main()
{
	int num, i, countZ=0,countF=0, count0=0;
	printf("输入10个数\n");
	for (i = 0; i < 10; i++)
	{
		scanf("%d", &num);
		if (num > 0)
			countZ += 1;
		if (num < 0)
			countF += 1;
		if (num == 0)
			count0 += 1;
	}
	printf("正数的个数为%d\n", countZ);
	printf("负数的个数为%d\n", countF);
	printf("零的个数为%d\n", count0);
	return 0;
}