201509-2-日期计算-ccf

 题目：http://118.190.20.162/view.page?gpid=T31

解题思路：简单模拟

#include<iostream>
#include<cstdio>
using namespace std;
bool yun(int n){
    if(n%4==0&&n%100!=0||n%400==0){
        return true;
    }
return false;
}
int main(){
    int m[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
    int n,ds,days=0;
    cin>>n;
    cin>>ds;
    int k,day=0;
    if(yun(n)) m[2]++;
    for(int i=0;i<=12;i++){
        days+=m[i];
        if(ds<=days){
            k=i;
            day=ds-(days-m[i]);
            break;
        }
     }
     cout<<k<<endl;
     cout<<day<<endl;
return 0;
}