LeetCode703 Kth Largest Element in a Stream(求第K大元素)

Design a class to find the kth largest element in a stream. Note that it is the kth largest element in the sorted order, not the kth distinct element.

Your KthLargest class will have a constructor which accepts an integer k and an integer array nums, which contains initial elements from the stream. For each call to the method KthLargest.add, return the element representing the kth largest element in the stream.

 Example:

int k = 3;
int[] arr = [4,5,8,2];
KthLargest kthLargest = new KthLargest(3, arr);
kthLargest.add(3);   // returns 4
kthLargest.add(5);   // returns 5
kthLargest.add(10);  // returns 5
kthLargest.add(9);   // returns 8
kthLargest.add(4);   // returns 8​​​​​​

【思路一】保存前K个最大的值,每次加入新数字后,如果比之前K个中的min还小,则不做任何操作;如果大于min,则把这些数重新排列,然后删除掉最小的值继续保留前k个最大值。时间复杂度为O(N*KlogK)。

【思路二】用优先队列,维护一个小顶堆(Min Heap),Size = K。复杂度为:O(N*logK)

class KthLargest {
public:
    KthLargest(int k, vector<int> nums) {
        size = k;
        for(auto num:nums){
            q.push(num);
            if(q.size() > size)
                q.pop();
        }
    }
    
    int add(int val) {
        q.push(val);
        if(q.size() > size)
            q.pop();
        return q.top();
    }
private:
    priority_queue<int,vector<int>, greater<int> > q;
    int size;
};

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转载自blog.csdn.net/zpznba/article/details/84024005