Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the absolute difference between i and j is at most k.
Example 1:
Input: nums = [1,2,3,1], k = 3 Output: true
Example 2:
Input: nums = [1,0,1,1], k = 1 Output: true
Example 3:
Input: nums = [1,2,3,1,2,3], k = 2 Output: false
LeetCode:链接
用哈希表,如果再次在字典中出现并且index不大于k,就返回True,否则就重新赋值。
如果K个数之后还没有找到重复的,就删除字典中存储的东西,也是一种方法。
class Solution(object):
def containsNearbyDuplicate(self, nums, k):
"""
:type nums: List[int]
:type k: int
:rtype: bool
"""
dict = {}
for i in range(len(nums)):
if nums[i] in dict and i - dict[nums[i]] <= k:
return True
dict[nums[i]] = i
return False