课件中动手动脑5

(1)多层的异常捕获1

源代码:

public class catch1 {
    public static void main(String[] args) {
        // TODO Auto-generated method stub
        try { 
            try { 
                throw new ArrayIndexOutOfBoundsException(); 
            } 
            catch(ArrayIndexOutOfBoundsException e) { 
                   System.out.println(  "ArrayIndexOutOfBoundsException" +  "/内层try-catch"); 
            }
        throw new ArithmeticException(); 
    } 
    catch(ArithmeticException e) { 
        System.out.println("发生ArithmeticException"); 
    } 
    catch(ArrayIndexOutOfBoundsException e) { 
       System.out.println(  "ArrayIndexOutOfBoundsException" + "/外层try-catch"); 
    } 
    }
}

运行结果:

我对源代码及运行结果的理解:

内层的try抛出ArrayIndexOutOfBoundsException异常然后被内层的catch捕捉,并输出结果中的第一行,然后异常因为被捕捉,继续执行外层try中的语句,抛出了ArithmeticException异常,被外层的catch语句捕捉后输出结果中的第二行。

(1)多层的异常捕获2

源代码:

public class catch2 {
    public static void main(String[] args) {
        // TODO Auto-generated method stub
        try {
            try { 
                throw new ArrayIndexOutOfBoundsException(); 
            } 
            catch(ArithmeticException e) { 
                System.out.println( "ArrayIndexOutOfBoundsException" + "/内层try-catch"); 
            }
        throw new ArithmeticException(); 
    } 
    catch(ArithmeticException e) { 
        System.out.println("发生ArithmeticException"); 
    } 
    catch(ArrayIndexOutOfBoundsException e) { 
        System.out.println( "ArrayIndexOutOfBoundsException" + "/外层try-catch"); 
    } 
    }
}

运行结果:

我对源代码及运行结果的理解:

内层的try中抛出了异常ArrayIndexOutOfBoundsException,在内层的catch中没有办法捕捉,就跳出了外层的try,被外层的catch捕捉,此时外层的try语句中还有没有被执行的则直接跳过继续向下执行。

(1)finally执行机制:

源代码:

public class finally1 {
    public static void main(String[] args) {
    int result;        
        try {            
            System.out.println("in Level 1");           
             try {                
                System.out.println("in Level 2");
  result=100/0;  //Level 2               
                 try {                   
                     System.out.println("in Level 3");                      
                     //result=100/0;  //Level 3                
                }                 
                catch (Exception e) {                    
                    System.out.println("Level 3:" + e.getClass().toString());                
                }                               
                finally {                    
                    System.out.println("In Level 3 finally");                
                }                            
                // result=100/0;  //Level 2            
                }            
            catch (Exception e) {               
                 System.out.println("Level 2:" + e.getClass().toString());          
             }
             finally {                
                System.out.println("In Level 2 finally");           
             }             
            // result = 100 / 0;  //level 1        
        }         
        catch (Exception e) {            
            System.out.println("Level 1:" + e.getClass().toString());        
        }        
        finally {         
         System.out.println("In Level 1 finally");
        }    
    }
}

运行结果:

我对源代码及运行结果的理解:

在多层的try。。Catch()。。Finally执行时,某一层有错误被抛出后,该错误只能被本层或者外层的catch所捕捉,也就意味着该错误一旦出现,在其之后的所有语句不会被执行,直到其被本层或者更外层的catch所捕捉,该catch之后的语句才能被执行,也就是只有该catch所在的那一层以及更外层的finally语句才能被执行。

4finally语句块一定会执行吗?

public class finally2 {
    public static void main(String[] args) {
        // TODO Auto-generated method stub
try{            
            System.out.println("in main");           
            throw new Exception("Exception is thrown in main");
                    //System.exit(0);        
        }       
        catch(Exception e)
            {            
            System.out.println(e.getMessage());            
            System.exit(0);        
        }       
        finally        
        {            
            System.out.println("in finally");        
        }
    }
}

运行结果:

我对源代码及运行结果的理解:

在执行catch()语句时,调用了Systemexitint)方法正常退出,程序就终止了,就不会执行下面的finally语句,所以finally虽用来殿后但并不必须执行。

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转载自www.cnblogs.com/123456www/p/9944127.html
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