[LeetCode] 404. Sum of Left Leaves

题：https://leetcode.com/problems/sum-of-left-leaves/description/

题目

Find the sum of all left leaves in a given binary tree.

Example:

    3
   / \
  9  20
    /  \
   15   7

There are two left leaves in the binary tree, with values 9 and 15 respectively. Return 24.

题目大意

求所有左叶子的和。其中左叶子的定义为：1.为叶子；2.为某结点的左子树。

思路

先序遍历，若一个结点为左子树为 叶子，那么累加。

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
class Solution {
    int tsum = 0;
    public void dfs(TreeNode root){
        if(root == null)
            return;
        if(root.left != null && root.left.left == null && root.left.right == null)
            tsum += root.left.val;
        
        dfs(root.left);
        dfs(root.right);
    }
    public int sumOfLeftLeaves(TreeNode root) {
        dfs(root);
        return tsum;
    }
}