leetcode: 111. Minimum Depth of Binary Tree

版权声明:转载请注明出处 https://blog.csdn.net/JNingWei/article/details/83817430

Difficulty

Easy.

Problem

Given a binary tree, find its minimum depth.

The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node.

Note: A leaf is a node with no children.

Example:

Given binary tree [3,9,20,null,null,15,7],

    3
   / \
  9  20
    /  \
   15   7
return its minimum depth = 2.

AC

# Definition for a binary tree node.
# class TreeNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None


class Solution():
    def minDepth(self, root):
        if not root:
            return 0
        if not root.left or not root.right:
            return self.minDepth(root.left) + self.minDepth(root.right) + 1
        else:
            return min(self.minDepth(root.right), self.minDepth(root.left)) + 1

猜你喜欢

转载自blog.csdn.net/JNingWei/article/details/83817430