- 定义了一个函数findname.py,获得含有关键字的列表名称,并返回list最大值;
def fnn(names, keys): k = [] for name in names: #循环获得属性为value的值 s = name.get_attribute("value") #找到包含关键字keys的字符串 if keys in s: k.append(s) newest = max(k) return newest
#先定位到列表,在定位input,返回list names = driver.find_element_by_xpath( "//*[@id='DataTables_Table_0']/tbody").find_elements_by_tag_name("input") #关键字keys为zs name = findname.fnn(names, "zs") driver.find_element_by_link_text(name).click()
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字符串包含判断:关键字 in string;
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def fnn(names, keys): k = [] for name in names: #循环获得属性为value的值 s = name.get_attribute("value") #找到包含关键字keys的字符串 if keys in s: k.append(s) newest = max(k) return newest