批量获取mysql用户权限的方法


-- 服务器级别的权限


select  a.GRANTEE,GROUP_CONCAT(a.PRIVILEGE_TYPE),
concat("grant ",GROUP_CONCAT(a.PRIVILEGE_TYPE)," ON  *.* to " ,a.GRANTEE  )
from   USER_PRIVILEGES a 
GROUP BY GRANTEE ;



-- db 级别的权限

select GRANTEE,TABLE_SCHEMA,GROUP_CONCAT(PRIVILEGE_TYPE),
concat("grant ",GROUP_CONCAT(PRIVILEGE_TYPE)," ON  ",TABLE_SCHEMA,".* to " ,GRANTEE  )
 from   information_schema.SCHEMA_PRIVILEGES
GROUP BY GRANTEE,TABLE_SCHEMA ;



-- 表级别的权限

select GRANTEE,TABLE_SCHEMA,table_name,GROUP_CONCAT(PRIVILEGE_TYPE),
concat("grant ",GROUP_CONCAT(PRIVILEGE_TYPE)," ON  ",TABLE_SCHEMA,".",table_name," to " ,GRANTEE  )
 from   information_schema.TABLE_PRIVILEGES
GROUP BY GRANTEE,TABLE_SCHEMA,table_name ;


-- 列级别权限

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select GRANTEE,TABLE_SCHEMA,table_name,COLUMN_NAME,GROUP_CONCAT(PRIVILEGE_TYPE) from   information_schema.COLUMN_PRIVILEGES
GROUP BY GRANTEE,TABLE_SCHEMA,table_name,COLUMN_NAME ;



-- 获取用户权限和密码(密文)

select  a.GRANTEE,GROUP_CONCAT(a.PRIVILEGE_TYPE),
concat("grant ",GROUP_CONCAT(a.PRIVILEGE_TYPE)," ON  *.* to " ,a.GRANTEE ," identified by password '",c.authentication_string,"';" ) privi
from   USER_PRIVILEGES a left  join  mysql.user c on a.GRANTEE = concat("'",c.user,"'","@","'",c.host,"'") 
GROUP BY GRANTEE ;


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转载自blog.51cto.com/dwchaoyue/2313318