private long exitTime = 0; @Override public boolean onKeyDown(int keyCode, KeyEvent event) { if(keyCode == KeyEvent.KEYCODE_BACK && event.getAction() == KeyEvent.ACTION_DOWN){ if((System.currentTimeMillis()-exitTime) > 2000){ MyToast.showToast(MainActivity.this, "再按一次退出程序", 2); exitTime = System.currentTimeMillis(); } else { finish(); System.exit(0); } return true; } return super.onKeyDown(keyCode, event); }
Android再按一次退出程序实现方法
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转载自geoffrey-qiao.iteye.com/blog/2235526
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