Java 8 获取某天最大(23:59:59)最小(00:00:00)时间

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Java 8 中获取某一天最大时间和最小时间如下：

import java.text.SimpleDateFormat;
import java.time.Instant;
import java.time.LocalDateTime;
import java.time.LocalTime;
import java.time.ZoneId;
import java.util.Date;

public class GetMaxMinTime {
	public static void main(String[] args) {
		Date date = new Date();
		
		System.out.println("今天开始时间：" + getStartOfDay(date));
		System.out.println("今天结束时间：" + getEndOfDay(date));
		
		SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
		
		System.out.println(sdf.format(getStartOfDay(date)));
		System.out.println(sdf.format(getEndOfDay(date)));
		
	}
	
	// 获得某天最大时间 2017-10-15 23:59:59
	public static Date getEndOfDay(Date date) {
		LocalDateTime localDateTime = LocalDateTime.ofInstant(Instant.ofEpochMilli(date.getTime()), ZoneId.systemDefault());;
		LocalDateTime endOfDay = localDateTime.with(LocalTime.MAX);
		return Date.from(endOfDay.atZone(ZoneId.systemDefault()).toInstant());
	}
	
	// 获得某天最小时间 2017-10-15 00:00:00
	public static Date getStartOfDay(Date date) {
		LocalDateTime localDateTime = LocalDateTime.ofInstant(Instant.ofEpochMilli(date.getTime()), ZoneId.systemDefault());
		LocalDateTime startOfDay = localDateTime.with(LocalTime.MIN);
		return Date.from(startOfDay.atZone(ZoneId.systemDefault()).toInstant());
	}

}

结果输出如下：