循环计算n的阶乘

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循环计算n的阶乘

#include<iostream>
#include<ctime>

using namespace std;

double f(int x)
{
	if (x < 0)
		return 0;
	else if (x == 0)
		return 1;
	else
		return x*f(x - 1);

}

int main()
{
	//反复输入，计算阶乘
	int n;
	for (;;)
	{
		cout << "请输入一个正整数：";
		cin >> n;
		if (n == 0)
			break;
		if (n < 0)
		{
			cout << "不能是负数" << endl;
			continue;
		}
			
		cout << n << "的阶乘为：" << f(n) << endl;
	}
	return 0;
}