java实现:(似乎是只能处理正数)
import java.io.*;
import java.math.BigInteger;
import java.util.*;
public class Main {
public static Scanner s = new Scanner(System.in);
public static void main(String args[]) throws Exception {
int t;
t = s.nextInt();
while(t-- != 0)
{
BigInteger x;
BigInteger sum = new BigInteger("0");
for (int i = 1; i <= 4; i++)
{
x = s.nextBigInteger();
sum = sum.add(x);
}
System.out.println(sum);
}
}
}
C++实现:(只能处理正数)
#include<iostream>
#include<cstring>
using namespace std;
string sum(string s1,string s2)
{
if(s1.length()<s2.length())
{
string temp=s1;
s1=s2;
s2=temp;
}
int i,j;
for(i=s1.length()-1,j=s2.length()-1; i>=0; i--,j--)
{
s1[i]=char(s1[i]+(j>=0?s2[j]-'0':0));
if(s1[i]-'0'>=10)
{
s1[i]=char((s1[i]-'0')%10+'0');
if(i) s1[i-1]++;
else s1='1'+s1;
}
}
return s1;
}
int main()
{
int t;
string a,b,c,d;
while(cin>>t)
{
while(t--)
{
cin>>a>>b>>c>>d;
a=sum(a,b);
c=sum(c,d);
a=sum(a,c);
cout<<a<<endl;
}
}
return 0;
}