二柱子——在线答题

设计思想：

首先考虑可以让程序执行后出现5个随机加减乘除的算式，数的大小控制在100以内；
其次要实现在线答题，就要用程序控制在出完题以后可以在后面继续输入答案，答案之间用空格隔开，并对做题人给出的答案进行判断，正确的不予以提示，错误的在提示错误后并显示在屏幕上，并将错题记录在错题本txt文档中以便后续的复习

源程序代码：

#include <stdio.h>
#include <stdlib.h> 
#include <time.h>

int main(){
    FILE *fp;
    int answer[10];
    int myanswer[10];
    int i, j, num, m, num1, num2, scc;
    srand(time(0));
    char sc[] = {'+', '-', '*', '/'};
    char cnt = 0;
    char c;
    int str[10][6];
    printf("欢迎使用简易答题系统：\n\n");
    
    for(i=0; i<5; i++){
        m = 1;
        for(j=0; j<m; j++)
        {
            num1 = rand() % 10 + 1;
        }
        num2 = rand() % 10 + 1;
        scc = rand() % 4;
        if(scc == 3 && num1 % num2 != 0){
            i--;
            continue;
        }
        str[i][0] = num1;
        str[i][1] = (int)sc[scc];
        str[i][2] = num2;
        if(scc == 0) answer[cnt++] = num1 + num2;
        if(scc == 1) answer[cnt++] = num1 - num2;
        if(scc == 2) answer[cnt++] = num1 * num2;
        if(scc == 3) answer[cnt++] = num1 / num2;
        printf("%d %c %d =\n", num1, sc[scc], num2);
    }

    
    
    printf("\n\n请输入你的答案：");
    cnt = 0;
    fp = fopen("wrong.txt", "a");
    scanf("%d%d%d%d%d", &myanswer[0], &myanswer[1], &myanswer[2], &myanswer[3], &myanswer[4]);
    for(i=0; i<5; i++){
        if(answer[i] != myanswer[i]){
            cnt++;
            fprintf(fp, "%d %c %d = %d\n", str[i][0], (char)str[i][1], str[i][2], myanswer[i]);
            printf("%d %c %d = %d\n", str[i][0], (char)str[i][1], str[i][2], myanswer[i]);
        }
    }
    fclose(fp);
    if(cnt > 0) printf("做错了%d道题，请查阅wrong.txt及时复习", cnt); 
    return 0;
} 

项目计划总结：

运行结果截图：