PAT-BASIC1006——换个格式输出整数

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我的PAT-BASIC代码仓:https://github.com/617076674/PAT-BASIC

原题链接:https://pintia.cn/problem-sets/994805260223102976/problems/994805318855278592

题目描述:

知识点:字符串

思路:用一个数组来存储1、2、3、4、5、6、7、8、9对应的字符串

题给的正整数不超过3位,因此时间复杂度和空间复杂度分析没有必要。

C++代码:

#include<iostream>
#include<vector>
#include<string>

using namespace std;

int main() {
	int num;
	cin >> num;
	
	vector<int> nums;
	while (num > 0) {
		nums.push_back(num % 10);
		num /= 10;
	}
	string result;
	string strings[] = { "1", "12", "123", "1234", "12345", "123456", "1234567", "12345678", "123456789" };
	if (nums.size() == 3) {
		while (nums[2] > 0) {
			nums[2]--;
			result += "B";
		}
		while (nums[1] > 0) {
			nums[1]--;
			result += "S";
		}
		if (nums[0] != 0) {
			result += strings[nums[0] - 1];
		}
	} else if (nums.size() == 2) {
		while (nums[1] > 0) {
			nums[1]--;
			result += "S";
		}
		if (nums[0] != 0) {
			result += strings[nums[0] - 1];
		}
	} else {
		if (nums[0] != 0) {
			result += strings[nums[0] - 1];
		}
	}
	cout << result;
}

C++解题报告:

JAVA代码:

import java.util.ArrayList;
import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        String[] strings = {"1", "12", "123", "1234", "12345", "123456", "1234567", "12345678", "123456789"};
        Scanner scanner = new Scanner(System.in);
        int num = scanner.nextInt();
        ArrayList<Integer> arrayList = new ArrayList<>();
        while(num > 0){
            arrayList.add(num % 10);
            num /= 10;
        }
        StringBuilder stringBuilder = new StringBuilder();
        if(arrayList.size() == 3){
            for (int i = 0; i < arrayList.get(2); i++) {
                stringBuilder.append("B");
            }
            for (int i = 0; i < arrayList.get(1); i++) {
                stringBuilder.append("S");
            }
            if(arrayList.get(0) != 0) {
                stringBuilder.append(strings[arrayList.get(0) - 1]);
            }
        }else if(arrayList.size() == 2){
            for (int i = 0; i < arrayList.get(1); i++) {
                stringBuilder.append("S");
            }
            if(arrayList.get(0) != 0) {
                stringBuilder.append(strings[arrayList.get(0) - 1]);
            }
        }else{
            if(arrayList.get(0) != 0) {
                stringBuilder.append(strings[arrayList.get(0) - 1]);
            }
        }
        System.out.println(stringBuilder.toString());
    }
}

JAVA解题报告:

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转载自blog.csdn.net/qq_41231926/article/details/83213358