32. 将employees表的所有员工的last_name和first_name拼接起来作为Name

题目描述

将employees表的所有员工的last_name和first_name拼接起来作为Name，中间以一个空格区分
CREATE TABLE `employees` ( `emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));

输入描述:

无

输出描述:

Name
Facello Georgi
Simmel Bezalel
Bamford Parto
Koblick Chirstian
Maliniak Kyoichi
Preusig Anneke 扫描二维码关注公众号，回复： 3653406 查看本文章
Zielinski Tzvetan
Kalloufi Saniya
Peac Sumant
Piveteau Duangkaew
Sluis Mary

1. SQLLite使用||进行字符串的拼接:

SELECT
	last_name || " " || first_name AS NAME
FROM
	employees;

 2. MySQL使用CONCAT或者CONCAT_WS两种函数进行字符串的拼接：

https://blog.csdn.net/qq_34436819/article/details/81154028

https://blog.csdn.net/qq_15783243/article/details/73234372

SELECT
	concat_ws(
		space(1),
		last_name,
		first_name
	) AS NAME
FROM
	employees;