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SELECT
a.id,a.name,a.dept_id,b.name,b.name_path, REVERSE( LEFT( REVERSE(b.name_path),LOCATE('→' , REVERSE(b.name_path) )-1) ) ,REVERSE(SUBSTRING(REVERSE(b.name_path),LOCATE('→' , REVERSE(b.name_path) )+1,LENGTH(b.name_path))),1
FROM(
SELECT
id,name,dept_id
FROM
security_org_position where data_state=1 and `name`='文秘'
) a INNER JOIN security_org_department b on a.dept_id=b.id where b.data_state=1 and b.level2!=30000 and b.level3=3 ;
REVERSE( LEFT( REVERSE(b.name_path),LOCATE('→' , REVERSE(b.name_path) )-1) ) 反转顺序获取第一次符号出现的位置截取
REVERSE(SUBSTRING(REVERSE(b.name_path),LOCATE('→' , REVERSE(b.name_path) )+1,LENGTH(b.name_path))) 反转获取特殊符号第一次出现的位置，从指定位置获取符号前面的数据
