版权声明:本文为博主原创文章,转载文章须附上文章来源与作者。 https://blog.csdn.net/ChangerJJLee/article/details/81095126
对于结构体来说,一个是 Phone类型,实现了PhoneFunction接口,这种情况下,无论是Phone还是*Phone都是可以成为接口调用的
package main
import "fmt"
type Phone struct {
OS string
Net string
}
type PhoneFunction interface {
Communicate()
Online()
}
func Call(OnePhone PhoneFunction) {
OnePhone.Communicate()
}
func QQ(OnePhone PhoneFunction) {
OnePhone.Online()
}
func (p Phone) Communicate() {
fmt.Printf("...呼叫中 \n")
}
func (p Phone) Online() {
fmt.Printf("...上网中 \n")
}
func main() {
p := &Phone{"ios", "5G"}
fmt.Printf("%+v ", p)
Call(p)
QQ(p)
t := Phone{"Android","5G"}
fmt.Printf("%+v ", t)
Call(t)
QQ(t)
}
- 若将如下方法改成指针接受者,将编译失败
func (p Phone) Communicate() {
fmt.Printf("...呼叫中 \n")
}
func (p Phone) Online() {
fmt.Printf("...上网中 \n")
}
# command-line-arguments
src\6_面向对象\OO\oo1\oo1.go:43:6: cannot use t (type Phone) as type PhoneFunction in argument to Call:
Phone does not implement PhoneFunction (Communicate method has pointer receiver)
src\6_面向对象\OO\oo1\oo1.go:44:4: cannot use t (type Phone) as type PhoneFunction in argument to QQ:
Phone does not implement PhoneFunction (Communicate method has pointer receiver)
要想编译通过将 t := Phone{“Android”,”5G”}改为t := &Phone{“Android”,”5G”},此时继承的意义也就不存在了
总结
1.在接口中的method,对于普通类型T,T的methods set里不会继承包含*T实现的method,
2.除非T自己实现相对应的method。
3.但是,*T会继承T的method set