374. Guess Number Higher or Lower

We are playing the Guess Game. The game is as follows:

I pick a number from 1 to n. You have to guess which number I picked.

Every time you guess wrong, I'll tell you whether the number is higher or lower.

You call a pre-defined API guess(int num) which returns 3 possible results (-11, or 0):

-1 : My number is lower
 1 : My number is higher
 0 : Congrats! You got it!

Example:

n = 10, I pick 6.

Return 6.

题意:

猜数字,有一个内置的函数guess,如果目标数字大于我们猜的,就返回1,小于则返回-1,相等就返回0.

思路:

二分法。设置l和r,初始值分别为1,n。不取0是因为题目说明1-n,并且注意题目说的my number是指目标数字。

代码:

/* The guess API is defined in the parent class GuessGame.
   @param num, your guess
   @return -1 if my number is lower, 1 if my number is higher, otherwise return 0
      int guess(int num); */

public class Solution extends GuessGame {
    public int guessNumber(int n) {
        int l=1,r=n;
        while(l<=r)
        {
            int t=l+(r-l)/2;
            if(guess(t)==1)
                l=t+1;
            else if(guess(t)==-1)
                r=t-1;
            else
                return t;
        }
        return -1;
    }
}

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转载自blog.csdn.net/qq_36718317/article/details/80257742
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