c++输入8个数取最大值和最小值(定义2个函数)

#include “stdafx.h”
#include
using namespace std;
int max(int b[],int n );
int min(int b[],int n);
int main()
{
int b[8];
for (int i = 0; i < 8; i++)
{
cin >> b[i];
}
cout << “最大值是:” << max(b, 8) << endl << “最小值是:” << min(b, 8) << endl;
return 0;
}
int max(int b[], int n) {
int max = b[0];
for (int i = 0; i < n; i++) {
if (b[i] > max)
max = b[i];
}
return max;
}
int min(int b[], int n) {
int min = b[0];
for (int i = 0; i < n; i++) {
if (b[i] < min)
min = b[i];
}
return min;
}

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转载自blog.csdn.net/weixin_43210805/article/details/82779772