Java-Lambda表达式

lambda定义:lambda是一个可传递的代码块,可以在以后执行一次或多次。

作用:可以灵活的改变方法中的执行过程,大大缩减代码量。

实例:

package test;

import java.awt.Event;
import java.awt.Toolkit;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.Comparator;
import java.util.Date;

import javax.swing.JOptionPane;
import javax.swing.Timer;

/** 
* @author HRX
* @version 创建时间:2018年9月11日 下午2:45:10 
* 类说明 
*/
public class ImplementTest{
	
	private int salary;
	private int bonus;
	
	public ImplementTest() {
	}
	
	public ImplementTest(int num , int bon) {
		this.salary = num;
		this.bonus = bon;
	}
	
//	public int compareTo(ImplementTest implementTest,ImplementTest implementTest1) {
//		// TODO Auto-generated method stub
//		return Integer.compare(implementTest.bonus, implementTest.bonus);
//	}
	
	public static class action implements ActionListener{

		@Override
		public void actionPerformed(ActionEvent e) {
			// TODO Auto-generated method stub
			System.out.println("......"+new Date());
			Toolkit.getDefaultToolkit().beep();
		}
		
	}
	
	public static void main(String[] args) {
		ArrayList<ImplementTest> arrayList = new ArrayList<>();
		ImplementTest i1 = new ImplementTest(1,10);
		ImplementTest i2 = new ImplementTest(3,20);
		ImplementTest i3 = new ImplementTest(6,30);
		ImplementTest i4 = new ImplementTest(10,40);
		ImplementTest i5 = new ImplementTest(5,50);
		arrayList.add(i1);
		arrayList.add(i2);
		arrayList.add(i3);
		arrayList.add(i4);
		arrayList.add(i5);
		Comparator<ImplementTest> c = null ;
//		arrayList.sort(c);
		Collections.sort(arrayList , (n1 , n2) -> n1.salary - n2.salary);
		for(ImplementTest i : arrayList)
			System.out.println(i.salary);
		
//		ActionListener a = new action();
//		Timer t = new Timer(1000, event -> {System.out.println("......"+new Date());
//			Toolkit.getDefaultToolkit().beep();});
//		t.start();
//		JOptionPane.showMessageDialog(null, "Stop?");
//		System.exit(0);
	}

}

从代码中可以看出,如果想跟据类ImplementTest的salary进行排序,则可使用

Collections.sort(arrayList , (n1 , n2) -> n1.salary - n2.salary);

如果想使用 类ImplementTest的bonus进行排序,则可使用

Collections.sort(arrayList , (n1 , n2) -> n1.bonus - n2.bonus);

其他的类似,就不在这一一列举。 

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转载自blog.csdn.net/qq_39429962/article/details/82686127