python练习—— 以行列互换形式输出列表

定义的列表：

tableDate = [['apples','oranges','cherries','banana'],
             ['Alice','Bob','Carol','David'],
             ['dogs','cats','moose','goose']]

输出形式：

   apples Alice  dogs
  oranges   Bob  cats
 cherries Carol moose
   banana David goose

直接贴代码：

#定义一个表
tableDate = [['apples','oranges','cherries','banana'],
             ['Alice','Bob','Carol','David'],
             ['dogs','cats','moose','goose']]

#保存每行最长字符串的长度：
col_len = [len(tableDate[0][0]),len(tableDate[1][0]),len(tableDate[2][0])]

#循环求出每行的最长字符串长度：
for j in range(len(tableDate)):
    for i in range(len(tableDate[j])):
        if(col_len[j] < len(tableDate[j][i])):
            col_len[j] = len(tableDate[j][i])

#保证每行输出为原先的列
for j in range(len(tableDate[0])):
    str = ''
    for i in range(len(tableDate)):
        str = str + tableDate[i][j].rjust(col_len[i]+1)
    print(str)