frameset不能写在body标签中
frame是单标签
设置frame的src属性；a标签的target属性要对应frame的name属性。
一 .实现
left.php
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>左侧内容</title>
</head>
<body>
<a href="yule.php" target="right1" >娱乐</a>
<a href="tiyu.php" target="right1">体育</a>
<a href="caijing.php" target="right1">财经</a>
</body>
</html>tiyu.php
<?php
echo "体育";
?>yule.php
<?php
echo "娱乐";
?>caijing.php
<?php
echo "财经";
?>frame.html (frameset不要写在body中)
<!DOCTYPE html>
<html>
<head>
<meta charset='utf-8'>
<title>Title</title>
</head>
<frameset cols="200,*">
<frame name="left1" src='left.php'>
<frame name='right1' src="caijing.php">
</frameset>
</html>效果：
二. 框架嵌套
frame.html
<!DOCTYPE html>
<html>
<head>
<meta charset='utf-8'>
<title>Title</title>
</head>
<frameset rows="60,*">
<frame name="top1" src='tiyu.php'>
<frameset cols="200,*">
<frame name='bottom1' src="yule.php">
<frame name='bottom2' src='caijing.php'>
</frameset>
</frameset>
</html>效果：
