C#LeetCode刷题之#83-删除排序链表中的重复元素（Remove Duplicates from Sorted List）

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问题

给定一个排序链表，删除所有重复的元素，使得每个元素只出现一次。

输入: 1->1->2

输出: 1->2

输入: 1->1->2->3->3

输出: 1->2->3

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Given a sorted linked list, delete all duplicates such that each element appear only once.

Input: 1->1->2

Output: 1->2

Input: 1->1->2->3->3

Output: 1->2->3

---

示例

public class Program {

    public static void Main(string[] args) {
        var head = new ListNode(1) {
            next = new ListNode(1) {
                next = new ListNode(2) {
                    next = new ListNode(3) {
                        next = new ListNode(3)
                    }
                }
            }
        };

        var res = DeleteDuplicates(head);
        ShowArray(res);

        Console.ReadKey();
    }

    private static void ShowArray(ListNode list) {
        var node = list;
        while(node != null) {
            Console.Write($"{node.val} ");
            node = node.next;
        }
        Console.WriteLine();
    }

    private static ListNode DeleteDuplicates(ListNode head) {
        if(head == null) return null;
        var cur = head;
        var next = cur.next;
        while(cur != null && next != null) {
            while(next != null && cur.val == next.val) {
                next = next.next;
            }
            cur.next = next;
            cur = next;
            next = cur?.next;
        }
        return head;
    }

    public class ListNode {
        public int val;
        public ListNode next;
        public ListNode(int x) { val = x; }
    }

}

以上给出1种算法实现，以下是这个案例的输出结果：

1 2 3

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分析：

显而易见，以上算法的时间复杂度为：  。