输入一段日期内的休息日和法定节假日

查询单日的有个现成的接口http://api.goseek.cn/  返回数据：工作日对应结果为 0, 休息日对应结果为 1, 节假日对应的结果为 2

要做的就是生成一年的日期,然后逐个去判断校验了.

具体的代码如下,实现的是输入一个时间段,能返回时间段内的休息日和节假日.里面有冗余的,没做修改,先这样吧

#coding:utf-8
import json
import urllib2
import  requests

import time
all_days=[]
def gener_data():
    """生成当年的所有日期"""
    year=time.strftime('%Y',time.localtime()) #得到年份
    months=[i for i in range(1,13)]
    for month in months:
        if month in [1,3,5,7,8,10,12]:
            for j in range(1,32):
                if j<10:
                    j='0{0}'.format(j)
                if month<10:
                    month='0%s'%month
                day='{0}{1}{2}'.format(year,month,j)
                all_days.append(day)
        elif month in [4,6,9,11]:
            for j in range(1,31):
                if j < 10:
                    j='0{0}'.format(j)
                if month < 10:
                    month='0{0}'.format(month)
                day = '{0}{1}{2}'.format(year, month, j)
                all_days.append(day)
        elif month==2:
            for j in range(1,29):
                if j < 10:
                    j = '0{0}'.format(j)
                if month < 10:
                    month = '0{0}'.format(month)
                day='{0}{1}{2}'.format(year, month, j)
                all_days.append(day)
            if int(year)%4==0:
                all_days.append('{0}0229'.format(year))

    return all_days

print gener_data()[gener_data().index('20181221'):gener_data().index('20181231')]
def get_holidays(start_date,end_date):
    dates =gener_data()[gener_data().index(start_date):gener_data().index(end_date)+1]
    holidays={}
    for dt in dates:
        url="http://api.goseek.cn/Tools/holiday?date={0}".format(dt)
        response_data=requests.get(url).json()['data']
        if response_data==1:
            holidays[dt]=1
        elif response_data==2:
            holidays[dt]=2
    value=sorted(holidays.items(),key=lambda holidays:holidays[0])
    return value

print get_holidays("20180601","20180630")