2018.09.22 列表的删除方法

# ppop()   # 删除列表里最后一位

L1 = [11,22,33,"alex","wusir",]
L1.pop()
print("结果:",L1)

print("------- end --------")


结果: [11, 22, 33, 'alex']
------- end --------
# ppop()   # 在括号里可以输入索引位置,然后删除

L1 = [11,22,33,"alex","wusir",]
L1.pop(3)
print("结果:",L1)

print("------- end --------")


结果: [11, 22, 33, 'wusir']
------- end --------
# remove # 指定索引删除

L1 = [11,22,33,"alex","wusir",]
L1.remove("alex")
print("结果:",L1)

print("------- end --------")


结果: [11, 22, 33, 'wusir']
------- end --------
# remove # 指定索引删除(只删除找到的第一个索引)

L1 = [11,22,33,"alex","wusir",11,]
L1.remove(11)
print("结果:",L1)

print("------- end --------")


结果: [22, 33, 'alex', 'wusir', 11]
------- end --------
# del # del是python全局性的删除指令,可以删除任何东西。

L1 = [11,22,33,"alex","wusir",11,]
del L1[1]
print("结果:",L1)

print("------- end --------")


结果: [11, 33, 'alex', 'wusir', 11]
------- end --------
# del # del是python全局性的删除指令,可以删除任何东西。

L1 = [11,22,33,"alex","wusir",11,]
del L1
print("结果:",L1)

print("------- end --------")


#    print("结果:",L1)
#NameError: name 'L1' is not defined
#  报错了,因为 L1 列表 已经被删除了。
# del # del 可以范围删除。

L1 = [11,22,33,"alex","wusir",11,]
del L1[3:5]
print("结果:",L1)

print("------- end --------")


结果: [11, 22, 33, 11]
------- end --------

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转载自www.cnblogs.com/boc1023/p/9689318.html