list里元素比大小，找出最大和最小

A = [1,2,3,4,5,6,8,9,10]


def findMinAndMax(L):
     n = 0
     Min = 0
     Max = 0
     # for i,value in enumerate(L):
         # print(i, value)
     for n in range(len(A)):
         a = L[n]
         b = L[n-1]
         if a < b:
             Min = a
             
         else:
             
             Max = a
     n = n + 1
     print('Min',Min,'Max',Max)
     return Min,Max
findMinAndMax(A)