C#中使用事件只启动一个实例

现有一个程序，只能启动一个实例：启动时，如果检测到实例已启动，则激活并显示到最前端；否则启动一个新的实例：
为此可以通过事件实现。
// 判断是否已启动
    bool IsFormExists(Form frmOwner_, string strEvent_)
        {
            EventWaitHandle eHandle;
            try
            {
                eHandle = EventWaitHandle.OpenExisting(strEvent_);
                // Form has start, close it
                eHandle.Set();    // 设定为有信号，已激活Restore线程
                eHandle.Close();
                frmOwner_.Close();
                return true;
            }
            catch (WaitHandleCannotBeOpenedException)
            {
            }

           // 第一个实例，创建事件，并启动线程
            eHandle = new EventWaitHandle(false, EventResetMode.ManualReset, strEvent_);
            Thread thrRestore = new Thread(new ParameterizedThreadStart(RestoreForm));
            thrRestore.IsBackground = true;
            FormParam stParam = new FormParam();
            stParam.frmOwner = frmOwner_;
            stParam.eHandle = eHandle;
            thrRestore.Start(stParam);

            return false;
        }

        delegate void DelNonParam();
        void RestoreForm(object oParam_)
        {
            FormParam stParam = (FormParam)oParam_;
            try
            {
                while (true)
                {
                    stParam.eHandle.WaitOne();
                    stParam.eHandle.Reset();

                    stParam.frmOwner.Invoke(new DelNonParam(delegate()
                        { // 激活实例，并显示到最前端
                            if (stParam.frmOwner.WindowState == FormWindowState.Minimized)
                                stParam.frmOwner.WindowState = FormWindowState.Normal;
                            stParam.frmOwner.BringToFront();
                            stParam.frmOwner.Activate();
                        })
                    );
                }
            }
            catch { }     
     }