Redis命令-有序集合-zremrangebylex

原文

http://redis.io/commands/zremrangebylex

简介

Remove all members in a sorted set between the given lexicographical range.

从有序集合中删除指定词典范围内的所有成员。

语法

ZREMRANGEBYLEX key min max

版本

Available since 2.8.9.

自2.8.9版本可用。

时间复杂度

Time complexity: O(log(N)+M) with N being the number of elements in the sorted set and M the number of elements removed by the operation.

O(log(N)+M):N是有序集合中元素的数量,M是要删除的元素的数量。

描述

When all the elements in a sorted set are inserted with the same score, in order to force lexicographical ordering, this command removes all elements in the sorted set stored at key between the lexicographical range specified by min and max.

当有序集合中插入的所有元素的分数相同时,为了强制词典排序,这个命令删除有序集合中词典范围在min到max内的所有元素。

The meaning of min and max are the same of the ZRANGEBYLEX command. Similarly, this command actually returns the same elements that ZRANGEBYLEX would return if called with the same min and max arguments.

min和max的含义与ZRANGEBYLEX命令相同。如果min和max参数相同,ZRANGEBYLEX命令返回相同的元素。

返回值

Integer reply: the number of elements removed.

Integer:被删除的元素的数量。

例子

redis>  ZADD myzset 0 aaaa 0 b 0 c 0 d 0 e
(integer) 5
redis>  ZADD myzset 0 foo 0 zap 0 zip 0 ALPHA 0 alpha
(integer) 5
redis>  ZRANGE myzset 0 -1
1) "ALPHA"
 2) "aaaa"
 3) "alpha"
 4) "b"
 5) "c"
 6) "d"
 7) "e"
 8) "foo"
 9) "zap"
10) "zip"
redis>  ZREMRANGEBYLEX myzset [alpha [omega
(integer) 6
redis>  ZRANGE myzset 0 -1
1) "ALPHA"
2) "aaaa"
3) "zap"
4) "zip"
redis> 

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转载自gitzhangyl.iteye.com/blog/2293273