SQLException: Parameter index out of range (1 > number of parameters, which is 0).异常

其他 2018-09-14 22:08:51 阅读次数: 0

今天在编写mybatsi编写like模糊查询的时候遇到一个报错,关于 Parameter index out of 异常,问题是这样的,在网上找了一下复制粘贴,果然没让我失望,报错

后来进过查百度,终于解决了........要是你遇到这样的问题,希望我的解决办法能帮到你!

解决的办法可以是这样........

WHERE channel_name LIKE CONCAT('%',#{channelName},'%')

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转载自blog.csdn.net/CoreyXuu/article/details/81987990

异常：java.sql.SQLException: Parameter index out of range (1 > number of parameters, which is 0)

SQLException: Parameter index out of range (1 > number of parameters, which is 0).异常

[异常]java.sql.SQLException: Parameter index out of range (1 > number of parameters, which is 0)

java.sql.SQLException: Parameter index out of range (1 > number of parameters, which is 0).

java.sql.SQLException:Parameter index out of range (1>number of parameters, which is 0)

java.sql.SQLException: Parameter index out of range (1 > number of parameters, which is 0)

java.sql.SQLException: Parameter index out of range (1 ＞ number of parameters, which is 0).

关于Parameter index out of range (1 > number of parameters, which is 0)

Parameter index out of range (1 > number of parameters, which is 0).

Parameter index out of range (1 > number of parameters, which is 0)

关于Parameter index out of range (1 > number of parameters, which is 0).

Parameter index out of range (1 ＞ number of parameters, which is 0).

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