int N = 10;
int M = 10;
int *a;
a = (int *) malloc(sizeof(int)*N);
int **aa;
aa = (int **) malloc(sizeof(int*)*N);
for(int i=0; i<N; i++)
{
aa[i] = (int *)malloc(sizeof(int)*M);
}
动态申请一维/二维数组
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转载自blog.csdn.net/Doutd_y/article/details/82498969
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