删除重复字符

给定两个字符,从第一个字符中删除在第二个字符中出现的字符

思路:通过字符的ascii码值作为下标,用数组构建一个哈希表

#include <iostream>
#include <string>
using namespace std;

class  Test{
        private:
                string a;
                int* hashtable;
        public:
                Test(string& x,string& y):a(x)
                {
                        hashtable = new int[122-65+1];
                        memset(hashtable,0,122-65+1);
                        for(int i=0;i<y.length();i++)
                        {
                                char p = y[i];
                                hashtable[p-'A']=1;
                        }

                        for(int i=0;i<a.length();i++)
                        {
                                if(hashtable[a[i]-'A']==1)
                                        a.erase(i,1);
                        }
                }

                ~Test()
                {       
                        delete[] hashtable;
                }

                void show()
                {       
                        cout<<a<<endl;
                }


};

int main()
{
string x="we are students";
string y="aeiou";

Test t(x,y);
t.show();
}

结果:

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转载自blog.csdn.net/ziggyPLAYguitar/article/details/82347722