JQ-AJAX-传递参数给success回调方法-AJAX自定义属性

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如果ajax方法在循环里面,但是又要传递参数给success回调方法,可以在AJAX自定义属性,然后直接在success方法中通过this调用即可。

var sites = {
"url1":"url1",
"url2":"url2",
}
for(var key in sites) {
    var site = key;
    $.ajax({
        url: 'www.example.com?url=' + site,
        site:site,
        dataType: "json",
        success: function(response,textStatus) {
            console.log(this.site);
        },
        error: function(response) {
        },
        complete: function() {
        }
    });
}

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转载自blog.csdn.net/wang704987562/article/details/82557857
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