【Newtonsoft.Json.dll】操作简单JSON数据

            //json数据
            string json = "{\"name\":\"张三\",\"sex\":\"男\",\"age\":\"20\",\"address\":\"北京\"}";

            //解析数据
            JObject data = JObject.Parse(json);

            //获取各属性的值
            string name = data["name"] + "";
            string sex = data["sex"] + "";
            string age = data["age"] + "";
            string address = data["address"] + "";