519. Random Flip Matrix & 710. Random Pick with Blacklist

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You are given the number of rows n_rows and number of columns n_cols of a 2D binary matrix where all values are initially 0. Write a function flip which chooses a 0 value uniformly at random, changes it to 1, and then returns the position [row.id, col.id] of that value. Also, write a function reset which sets all values back to 0. Try to minimize the number of calls to system's Math.random()and optimize the time and space complexity.

Note:

  1. 1 <= n_rows, n_cols <= 10000
  2. 0 <= row.id < n_rows and 0 <= col.id < n_cols
  3. flip will not be called when the matrix has no 0 values left.
  4. the total number of calls to flip and reset will not exceed 1000.

Example 1:

Input: 
["Solution","flip","flip","flip","flip"]
[[2,3],[],[],[],[]]
Output: [null,[0,1],[1,2],[1,0],[1,1]]

Example 2:

Input: 
["Solution","flip","flip","reset","flip"]
[[1,2],[],[],[],[]]
Output: [null,[0,0],[0,1],null,[0,0]]

Explanation of Input Syntax:

The input is two lists: the subroutines called and their arguments. Solution's constructor has two arguments, n_rows and n_colsflip and reset have no arguments. Arguments are always wrapped with a list, even if there aren't any.

模拟一遍1..row*col

import random

class Solution:

    def __init__(self, n_rows, n_cols):
        """
        :type n_rows: int
        :type n_cols: int
        """
        self.n_rows=n_rows
        self.n_cols=n_cols
        self.l=[[i,j,False] for j in range(n_cols) for i in range(n_rows)]
        self.cnt=n_rows*n_cols

    def flip(self):
        """
        :rtype: List[int]
        """
        idx=random.randint(1,self.cnt)
        p = 0
        while idx:
            while self.l[p][2]: p+=1
            idx-=1
            if idx==0: 
                self.l[p][2]=True
                self.cnt-=1
                return [self.l[p][0],self.l[p][1]]
            p+=1

    def reset(self):
        """
        :rtype: void
        """
        self.cnt=self.n_rows*self.n_cols
        self.l=[[i,j,False] for j in range(self.n_cols) for i in range(self.n_rows)]
        
        


# Your Solution object will be instantiated and called as such:
# obj = Solution(n_rows, n_cols)
# param_1 = obj.flip()
# obj.reset()

TLE,那就每次flip跟数字末尾的数swap一下

import random

class Solution:

    def __init__(self, n_rows, n_cols):
        """
        :type n_rows: int
        :type n_cols: int
        """
        self.n_rows=n_rows
        self.n_cols=n_cols
        self.l=[[i,j] for j in range(n_cols) for i in range(n_rows)]
        self.cnt=n_rows*n_cols

    def flip(self):
        """
        :rtype: List[int]
        """
        idx=random.randint(0,self.cnt-1)
        self.l[idx], self.l[self.cnt-1]=self.l[self.cnt-1], self.l[idx]
        self.cnt-=1
        return self.l[self.cnt]

    def reset(self):
        """
        :rtype: void
        """
        self.cnt=self.n_rows*self.n_cols
        


# Your Solution object will be instantiated and called as such:
# obj = Solution(n_rows, n_cols)
# param_1 = obj.flip()
# obj.reset()

继续TLE,看来还得优化建立数组这一过程,那就用Map,每次flip idx的时候,吧idx实际指向数组的最后一位

import random

class Solution:

    def __init__(self, n_rows, n_cols):
        """
        :type n_rows: int
        :type n_cols: int
        """
        self.n_rows=n_rows
        self.n_cols=n_cols
        self.d={}
        self.cnt=n_rows*n_cols

    def flip(self):
        """
        :rtype: List[int]
        """
        idx=random.randint(0,self.cnt-1)
        res=self.d.get(idx, idx)
        
        self.d[idx]=self.d.get(self.cnt-1, self.cnt-1)
        self.cnt-=1
        
        return res//self.n_cols, res%self.n_cols

    def reset(self):
        """
        :rtype: void
        """
        self.cnt=self.n_rows*self.n_cols
        self.d={}
        


# Your Solution object will be instantiated and called as such:
# obj = Solution(n_rows, n_cols)
# param_1 = obj.flip()
# obj.reset()

Given a blacklist B containing unique integers from [0, N), write a function to return a uniform random integer from [0, N) which is NOT in B.

Optimize it such that it minimizes the call to system’s Math.random().

Note:

  1. 1 <= N <= 1000000000
  2. 0 <= B.length < min(100000, N)
  3. [0, N) does NOT include N. See interval notation.

Example 1:

Input: 
["Solution","pick","pick","pick"]
[[1,[]],[],[],[]]
Output: [null,0,0,0]

Example 2:

Input: 
["Solution","pick","pick","pick"]
[[2,[]],[],[],[]]
Output: [null,1,1,1]

Example 3:

Input: 
["Solution","pick","pick","pick"]
[[3,[1]],[],[],[]]
Output: [null,0,0,2]

Example 4:

Input: 
["Solution","pick","pick","pick"]
[[4,[2]],[],[],[]]
Output: [null,1,3,1]

Explanation of Input Syntax:

The input is two lists: the subroutines called and their arguments. Solution's constructor has two arguments, N and the blacklist Bpick has no arguments. Arguments are always wrapped with a list, even if there aren't any.

类似的思路,要对blacklist先排序才work,因为是从末尾删除的,删除了就不能在修改了

import random

class Solution(object):

    def __init__(self, N, blacklist):
        """
        :type N: int
        :type blacklist: List[int]
        """
        self.cnt=N-1
        self.d={}
        blacklist.sort(reverse=True)
        for t in blacklist:
            self.d[t]=self.d.get(self.cnt, self.cnt)
            self.cnt-=1

    def pick(self):
        """
        :rtype: int
        """
        n=random.randint(0,self.cnt)
        return self.d.get(n, n)


# Your Solution object will be instantiated and called as such:
# obj = Solution(N, blacklist)
# param_1 = obj.pick()

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转载自blog.csdn.net/zjucor/article/details/82353031