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【华为OJ】【015-求int型数据在内存中存储时1的个数】
题目链接:
https://blog.csdn.net/DERRANTCM/article/details/51319753
C++实现:
void main()
{
int n1,n2,n3,n4;
string str1,strOut;
cin >> n1;
n2 = 0;
while(n1 != 0)
{
n2 += n1 & 0x01;
n1 >>= 1;
}
cout << n2 << endl;
system("pause");
}