要把数据进行合并达到下图的效果
jsp页面的代码如下：
<script type="text/javascript">
$(top.hangge());
$(document).ready(function(){
$("#table_report").rowspan(0);
$("#table_report").rowspan(1);
$("#table_report").rowspan1(8,1);
$("#table_report").rowspan1(9,1);
$("#table_report").rowspan1(10,1);
});
//jquery合并表格相同项
jQuery.fn.rowspan=function(colIdx){
return this.each(function(){
var that;
$('tr',this).each(function(row){
$('td:eq('+colIdx+')',this).filter(':visible').each(function(col){
if(that!=null && $(this).html()==$(that).html()){
rowspan=$(that).attr("rowSpan");
if(rowspan==undefined){
$(that).attr("rowSpan",1);
rowspan=$(that).attr("rowSpan");
}
rowspan=Number(rowspan)+1;
$(that).attr("rowspan",rowspan);
$(this).hide();
}else{
that=this;
}
});
});
});
}
//完善table表格合并功能，要求某一列前后行必须一致的情况下才去合并另一列（比如必须在前后行船名一致的情况下才考虑合并）
jQuery.fn.rowspan1 = function(colIdx,dataIdx) {//colIdx：要合并的列号，dataIdx：校验列号(值必须一致的列)
return this.each(function(){
var that;
var lastData;
$('tr', this).each(function(row) {//遍历行
var data_d = $(this).find('td').eq(dataIdx).html();//获取当前行校验列的值
if (lastData!=null && data_d == lastData) {//前后两条校验列的数据一致
$('td:eq('+colIdx+')', this).filter(':visible').each(function(col) {//处理要合并的列
if (that!=null && $(this).html() == $(that).html()) {//前后两条合并列的数据一致
rowspan = $(that).attr("rowSpan");
if (rowspan == undefined) {
$(that).attr("rowSpan",1);
rowspan = $(that).attr("rowSpan");
}
rowspan = Number(rowspan)+1;
$(that).attr("rowSpan",rowspan);
$(this).hide();
} else {
that = this;
}
});
} else {//如果前后两条校验列的数据不一致，则更新上一条的数据为本条数据
lastData = data_d;
$('td:eq('+colIdx+')', this).filter(':visible').each(function(col) {
that = this;
});
}
});
});
}
<script type="text/javascript">
有两种方法，前面的表格根据自己的情况来设置，后面的是比较完善的
xml里面的列，为了看的更加清楚：
<!--单船分析表 -->
<select id="datalistPageShipAls" parameterType="page" resultType="pd">
SELECT
A.R_SHIPS_NAME AS VAR1,
A.R_CARGO_NAME AS VAR2,
(SUBSTR(A.R_DATE,0,10))||'('||A.R_CLASSES||')' AS VAR3,
A.D_NAME AS VAR4,
A.MJ_NAME AS VAR5,
SUM(A.R_NET_WEIGHT) AS VAR6,
ROUND(SUM(A.R_TIME_USE/3600),2) AS VAR7,
ROUND(MAX(B.all_times/3600),2) AS VAR8,
MAX(B.all_weight) AS VAR9,
ROUND (MAX(B.all_weight)/MAX(B.all_times/3600),2) AS VAR10,
ROUND(SUM(A.R_NET_WEIGHT)/SUM(A.R_TIME_USE/3600),2) AS VAR11
FROM VW_DATA_DETAILS A,
(select S_ID,sum(r_time_use) as all_times,sum(r_net_weight) as all_weight from VW_DATA_DETAILS
where
1=1
<if test="pd.QUERY_BEGIN_DATE != null and pd.QUERY_BEGIN_DATE != '' and pd.QUERY_END_DATE != null and pd.QUERY_END_DATE != ''">
AND (R_DATE BETWEEN #{pd.QUERY_BEGIN_DATE} AND #{pd.QUERY_END_DATE})
</if>
group by S_ID
) B
WHERE
A.S_ID = B.S_ID
<if test="pd.QUERY_BEGIN_DATE != null and pd.QUERY_BEGIN_DATE != '' and pd.QUERY_END_DATE != null and pd.QUERY_END_DATE != ''">
AND (R_DATE BETWEEN #{pd.QUERY_BEGIN_DATE} AND #{pd.QUERY_END_DATE})
</if>
<if test="pd.R_SHIPS_NAME != null and pd.R_SHIPS_NAME != ''">
AND A.R_SHIPS_NAME LIKE CONCAT(CONCAT('%', #{pd.R_SHIPS_NAME}),'%')
</if>
GROUP BY R_SHIPS_NAME,R_CARGO_NAME,D_NAME,MJ_NAME,SUBSTR(R_DATE,0,10),R_CLASSES
ORDER BY R_SHIPS_NAME,(SUBSTR(R_DATE,0,10))||'('||R_CLASSES||')',D_NAME,MJ_NAME
</select>
起重获取数据用的是一个视图，因为这个项目涉及的的表格太多了。联合查询比较麻烦，希望遇到同样问题的朋友们，看到这个会对你们有点帮助，虽然我是一个菜鸟。。。
