Given an array nums
of n integers, are there elements a, b, c in nums
such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.
Note:
The solution set must not contain duplicate triplets.
Example:
Given array nums = [-1, 0, 1, 2, -1, -4], A solution set is: [ [-1, 0, 1], [-1, -1, 2] ]
C++:
1 class Solution { 2 public: 3 vector<vector<int>> threeSum(vector<int>& nums) { 4 vector<vector<int>> result; 5 if (nums.size() <= 2)return result; 6 sort(nums.begin(), nums.end()); 7 for (int i = 0; i < nums.size() - 2; i++) { 8 int a = nums[i]; 9 if (a > 0) break; 10 if (i > 0 && a == nums[i - 1]) continue; 11 for (long j = i + 1, k = nums.size() - 1; j < k;) { 12 int b = nums[j]; 13 int c = nums[k]; 14 int value = a + b + c; 15 if (value == 0) { 16 result.push_back(vector<int>({ a, b, c })); 17 while (b == nums[++j] && j<k); 18 while (c == nums[--k] && j<k); 19 } 20 else if (value > 0) { 21 k--; 22 } 23 else { 24 j++; 25 } 26 } 27 } 28 return result; 29 } 30 };