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1，内容回顾
补充：主键
一个表只能有一个主键
主键可以由多列组成
补充：外键 ?
CREATE TABLE t5 (
nid int(11) NOT NULL AUTO_INCREMENT,
pid int(11) not NULL,
num int(11),
primary key(nid,pid)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
create table t6(
id int auto_increment primary key,
name char(10),
id1 int,
id2 int,
CONSTRAINT fk_t5_t6 foreign key (id1,id2) REFERENCES t1(nid,pid)
)engine=innodb default charset=utf8;2，sql操作
1）自增
对于自增补充：
show create table t10;
show create table t10 \G;
alter table t10 AUTO_INCREMENT=20;
MySQL: 自增步长
基于会话级别（退出当前登录后步长设置失效）：
show session variables like 'auto_inc%'; 查看全局变量
set session auto_increment_increment=2; 设置会话步长
# set session auto_increment_offset=10;
基于全局级别：
show global variables like 'auto_inc%'; 查看全局变量
set global auto_increment_increment=2; 设置会话步长
# set global auto_increment_offset=10;2）唯一索引
create table t1(
id int ....,
num int,
xx int,
unique 唯一索引名称 (列名,列名),
constraint ....
)
#
1 1 1
2 1 2
PS:
唯一：
约束不能重复（可以为空）
PS: 主键不能重复（不能为空）
加速查找3）一对一
create table userinfo1(
id int auto_increment primary key,
name char(10),
gender char(10),
email varchar(64)
)engine=innodb default charset=utf8;
create table admin(
id int not null auto_increment primary key,
username varchar(64) not null,
password VARCHAR(64) not null,
user_id int not null,
unique uq_u1 (user_id),
CONSTRAINT fk_admin_u1 FOREIGN key (user_id) REFERENCES userinfo1(id)
)engine=innodb default charset=utf8;
4）多对多
reate table userinfo2(
id int auto_increment primary key,
name char(10),
gender char(10),
email varchar(64)
)engine=innodb default charset=utf8;
create table host(
id int auto_increment primary key,
hostname char(64)
)engine=innodb default charset=utf8;
create table user2host(
id int auto_increment primary key,
userid int not null,
hostid int not null,
unique uq_user_host (userid,hostid),
CONSTRAINT fk_u2h_user FOREIGN key (userid) REFERENCES userinfo2(id),
CONSTRAINT fk_u2h_host FOREIGN key (hostid) REFERENCES host(id)
)engine=innodb default charset=utf8;3， SQL语句数据行操作补充
create table tb12(
id int auto_increment primary key,
name varchar(32),
age int
)engine=innodb default charset=utf8;
增
insert into tb11(name,age) values('alex',12);
insert into tb11(name,age) values('alex',12),('root',18);
insert into tb12(name,age) select name,age from tb11;删
delete from tb12;
delete from tb12 where id !=2
delete from tb12 where id =2
delete from tb12 where id > 2
delete from tb12 where id >=2
delete from tb12 where id >=2 or name='alex'改
update tb12 set name='alex' where id>12 and name='xx'
update tb12 set name='alex',age=19 where id>12 and name='xx'查
select * from tb12;
select id,name from tb12;
select id,name from tb12 where id > 10 or name ='xxx';
select id,name as cname from tb12 where id > 10 or name ='xxx';
select name,age,11 from tb12;其他：
select * from tb12 where id != 1
select * from tb12 where id in (1,5,12);
select * from tb12 where id not in (1,5,12);
select * from tb12 where id in (select id from tb11)
select * from tb12 where id between 5 and 12;通配符：
select * from tb12 where name like "a%"
select * from tb12 where name like "a_"分页：
select * from tb12 limit 10;
select * from tb12 limit 0,10;
select * from tb12 limit 10,10;
select * from tb12 limit 20,10;
select * from tb12 limit 10 offset 20;
从第20行开始读取，读取10行；
结合Python分页：
# page = input('请输入要查看的页码')
# page = int(page)
# (page-1) * 10
# select * from tb12 limit 0,10; 1
# select * from tb12 limit 10,10;2
排序：
select * from tb12 order by id desc; 大到小
select * from tb12 order by id asc; 小到大
select * from tb12 order by age desc,id desc;
取后10条数据
select * from tb12 order by id desc limit 10;
分组：
select count(id),max(id),part_id from userinfo5 group by part_id;
count
max
min
sum
avg
**** 如果对于聚合函数结果进行二次筛选时？必须使用having ****
select count(id),part_id from userinfo5 group by part_id having count(id) > 1;
select count(id),part_id from userinfo5 where id > 0 group by part_id having count(id) > 1;连表操作：
select * from userinfo5,department5
select * from userinfo5,department5 where userinfo5.part_id = department5.id
select * from userinfo5 left join department5 on userinfo5.part_id = department5.id
select * from department5 left join userinfo5 on userinfo5.part_id = department5.id
# userinfo5左边全部显示
# select * from userinfo5 right join department5 on userinfo5.part_id = department5.id
# department5右边全部显示
select * from userinfo5 innder join department5 on userinfo5.part_id = department5.id
将出现null时一行隐藏
select * from
department5
left join userinfo5 on userinfo5.part_id = department5.id
left join userinfo6 on userinfo5.part_id = department5.id
select
score.sid,
student.sid
from
score
left join student on score.student_id = student.sid
left join course on score.course_id = course.cid
left join class on student.class_id = class.cid
left join teacher on course.teacher_id=teacher.tid
select count(id) from userinfo5;