常用组合数计算公式

版权声明:欢迎转载,不要求署名~~~ https://blog.csdn.net/shadandeajian/article/details/82084087
  • C n m = C n 1 m 1 + C n 1 m

  • m C n m = n C n 1 m 1

  • C n 0 + C n 1 + C n 2 + + C n n = 2 n

  • 1 C n 1 + 2 C n 2 + 3 C n 3 + + n C n n = n 2 n 1

  • 1 2 C n 1 + 2 2 C n 2 + 3 2 C n 3 + + n 2 C n n = n ( n + 1 ) 2 n 2

  • C n 1 1 C n 2 2 + C n 3 3 + + ( 1 ) n 1 C n n n = 1 + 1 2 + 1 3 + + 1 n

  • ( C n 0 ) 2 + ( C n 1 ) 2 + ( C n 2 ) 2 + + ( C n n ) 2 = C 2 n n

猜你喜欢

转载自blog.csdn.net/shadandeajian/article/details/82084087