关于结果处理类型input的代码演示-深入Struts2

一 Input因为年龄输入错误自动跳转回输入界面

1、struts.xml

<? xml version = "1.0" encoding = "UTF-8" ?>

<! DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.1//EN" " http://struts.apache.org/dtds/struts-2.1.dtd" ; >

< struts >

< package name = "default" namespace = "/" extends = "struts-default" >

< default-action-ref name = "index" ></ default-action-ref >

< action name = "index" >

< result > /error.jsp </ result >

</ action >

< action name = "*_*_*" method = "{2}" class = "com.cakin.{3}.{1}Action" >

< result > /result.jsp </ result >

< result name = "add" > /{2}. jsp </ result >

< result name = "update" > /{2}. jsp </ result >

</ action >

< action name = "LoginAction" method = "login" class = "com.cakin.action.LoginAction" >

< result > /success.jsp </ result >

< result name = "input" > /login.jsp </ result >

</ action >

</ package >

</ struts >

2、User.java

package com.cakin.po;

import java.util.List;

public class User {

private String username ;

private String password ;

private int age ;

public int getAge() {

return age ;

}

public void setAge( int age) {

this . age = age;

}

private List<User> booklist ;

public List<User> getBooklist() {

return booklist ;

}

public void setBooklist(List<User> booklist) {

this . booklist = booklist;

}

public String getUsername() {

return username ;

}

public void setUsername(String username) {

this . username = username;

}

public String getPassword() {

return password ;

}

public void setPassword(String password) {

this . password = password;

}

3、login.jsp

<%@ page language = "java" import = "java.util.*" pageEncoding = "utf-8" %>

String path = request.getContextPath();

String basePath = request.getScheme()+ "://" +request.getServerName()+ ":" +request.getServerPort()+path+ "/" ;

<! DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">

< html >

< head >

< base href = " <%= basePath %> " >

< title > My JSP 'login.jsp' starting page </ title >

< meta http-equiv = "pragma" content = "no-cache" >

< meta http-equiv = "cache-control" content = "no-cache" >

< meta http-equiv = "expires" content = "0" >

< meta http-equiv = "keywords" content = "keyword1,keyword2,keyword3" >

< meta http-equiv = "description" content = "This is my page" >

<!--

-->

</ head >

< body >

< form action = "LoginAction.action" method = "post" >

用户名： < input type = "text" name = "username" >

密码： < input type = "password" name = "password" >

书籍1： < input type = "text" name = "booklist[0].username" >

书籍2： < input type = "text" name = "booklist[1].username" >

年龄： < input type = "text" name = "age" >

< input type = "submit" value = "提交" />

</ form >

</ body >

</ html >

4、测试

二通过addFieldError跳回到输入页码，并带错误提示

1、struts.xml

<? xml version = "1.0" encoding = "UTF-8" ?>

<! DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.1//EN" " http://struts.apache.org/dtds/struts-2.1.dtd" ; >

< struts >

< package name = "default" namespace = "/" extends = "struts-default" >

< default-action-ref name = "index" ></ default-action-ref >

< action name = "index" >

< result > /error.jsp </ result >

</ action >

< action name = "*_*_*" method = "{2}" class = "com.cakin.{3}.{1}Action" >

< result > /result.jsp </ result >

< result name = "add" > /{2}. jsp </ result >

< result name = "update" > /{2}. jsp </ result >

</ action >

< action name = "LoginAction" method = "login" class = "com.cakin.action.LoginAction" >

< result > /success.jsp </ result >

< result name = "input" > /login.jsp </ result >

</ action >

</ package >

</ struts >

2、login.jsp

<%@ page language = "java" import = "java.util.*" pageEncoding = "utf-8" %>

<%@ taglib prefix = "s" uri = "/struts-tags" %>

String path = request.getContextPath();

String basePath = request.getScheme()+ "://" +request.getServerName()+ ":" +request.getServerPort()+path+ "/" ;

<! DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">

< html >

< head >

< base href = " <%= basePath %> " >

< title > My JSP 'login.jsp' starting page </ title >

< meta http-equiv = "pragma" content = "no-cache" >

< meta http-equiv = "cache-control" content = "no-cache" >

< meta http-equiv = "expires" content = "0" >

< meta http-equiv = "keywords" content = "keyword1,keyword2,keyword3" >

< meta http-equiv = "description" content = "This is my page" >

<!--

-->

</ head >

< body >

< form action = "LoginAction.action" method = "post" >

用户名： < input type = "text" name = "username" >< s:fielderror name = "username" ></ s:fielderror >

密码： < input type = "password" name = "password" >

书籍1： < input type = "text" name = "booklist[0].username" >

书籍2： < input type = "text" name = "booklist[1].username" >

年龄： < input type = "text" name = "age" >

< input type = "submit" value = "提交" />

</ form >

</ body >

</ html >

3、LoginAction

package com.cakin.action;

import com.cakin.po.User;

import com.opensymphony.xwork2.ActionSupport;

import com.opensymphony.xwork2.ModelDriven;

public class LoginAction extends ActionSupport implements ModelDriven<User>{

private User user =new User();

public String login(){

if(user.getUsername()==null

||"".equals(user.getUsername()))

{

this.addFieldError("username", "用户名为空");

return INPUT;

}

System.out.println(user.getUsername());

System.out.println(user.getBooklist().get(0).getUsername());

System.out.println(user.getBooklist().get(1).getUsername());

return SUCCESS;

}

@Override

public User getModel() {

// TODO Auto-generated method stub

return user;

}

4、测试

三通过validate方法实现调回到输入页码

1、LoginAction.jsp

package com.cakin.action;

import com.cakin.po.User;

import com.opensymphony.xwork2.ActionSupport;

import com.opensymphony.xwork2.ModelDriven;

public class LoginAction extends ActionSupport implements ModelDriven<User>{

private User user =new User();

public String login(){

System.out.println(user.getUsername());

System.out.println(user.getBooklist().get(0).getUsername());

System.out.println(user.getBooklist().get(1).getUsername());

return SUCCESS;

}

@Override

public void validate() {

// TODO Auto-generated method stub

if(user.getUsername()==null

||"".equals(user.getUsername()))

{

this.addFieldError("username", "用户名为空");

//return INPUT;

}

@Override

public User getModel() {

// TODO Auto-generated method stub

return user;

}

2、测试

关于结果处理类型input的代码演示-深入Struts2

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