题意:
给一个长度为n的数组,初始为a1,...,an
需要维护以下操作:
ADD l r x:给区间[l,r]上的所有元素+x
REVERSE l r:反转区间[l,r](比如:[1,2,3]反转后变成[3,2,1])
REVOLVE l r x:将区间[l,r]向前循环右移x位(比如:[1,2,3]循环右移2位变成[2,3,1])
INSERT P x:在位置P后插入一个x(比如:[1,2,3]在位置2后插入一个4变成[1,2,4,3])
DELETE P:删除位置P上的元素
MIN l r:求区间[l,r]的最小值
思路:
FHQ_Treap平衡树多操作合集
C++代码:
#include<map>
#include<set>
#include<stack>
#include<cmath>
#include<queue>
#include<vector>
#include<string>
#include<cstdio>
#include<cstring>
#include<complex>
#include<iostream>
#include<algorithm>
using namespace std;
#define ls ftr[k].l
#define rs ftr[k].r
typedef double DB;
typedef long long LL;
typedef complex<double>CD;
const int maxn = 200010;
const int mod = 1e9+7;
const int inf = 0x3f3f3f3f;
void Mod( int &x ){ x%=mod; }
int Min( int a , int b ){ return a<b?a:b; }
int Max( int a , int b ){ return a>b?a:b; }
int Random(){ static int seed = 703; return seed=(int)(seed*48271LL%2147483647); }
int root,sizes;
struct FHQ_Treap
{
int l,r;
int v,rnd;
int sizes;
int minx,rev,cnt;
}ftr[maxn];
void Addone( int k , int s )
{
if ( !k )
return;
ftr[k].v += s;
ftr[k].cnt += s;
ftr[k].minx += s;
}
void Revone( int k )
{
if ( !k )
return;
ftr[k].rev ^= 1;
swap ( ls , rs );
}
void Push_up( int k )
{
if ( !k )
return;
ftr[k].minx = Min ( ftr[k].v , Min( ftr[ls].minx , ftr[rs].minx ) );
ftr[k].sizes = ftr[ls].sizes+ftr[rs].sizes+1;
}
void Push_down( int k )
{
if ( !k )
return;
if ( ftr[k].cnt )
Addone( ls , ftr[k].cnt ),Addone( rs , ftr[k].cnt );
if ( ftr[k].rev )
Revone( ls ),Revone( rs );
ftr[k].cnt = 0;
ftr[k].rev = 0;
}
void Build( int &k , int s )
{
k = ++sizes;
ftr[k].l = 0;
ftr[k].r = 0;
ftr[k].v = s;
ftr[k].rnd = Random();
ftr[k].sizes = 1;
ftr[k].minx = s;
ftr[k].rev = 0;
ftr[k].cnt = 0;
}
void Split( int k , int &l , int &r , int s )
{
if ( s==0 )
l = 0,r = k;
else if ( s==ftr[k].sizes )
l = k,r = 0;
else if ( s<=ftr[ls].sizes )
Push_down( r=k ),Split( ls , l , ls , s ),Push_up( k );
else
Push_down( l=k ),Split( rs , rs , r , s-ftr[ls].sizes-1 ),Push_up( k );
}
void Merge( int &k , int l , int r )
{
if ( l==0||r==0 )
k = l+r;
else if ( ftr[l].rnd<ftr[r].rnd )
Push_down( k=l ),Merge( rs , rs , r ),Push_up( k );
else
Push_down( k=r ),Merge( ls , l , ls ),Push_up( k );
}
void Add( int l , int r , int s )
{
int x,y,z;
Split( root , x , y , r );
Split( x , z , x , l-1 );
Addone( x , s );
Merge( x , z , x );
Merge( root , x , y );
}
void Reverse( int l , int r )
{
int x,y,z;
Split( root , x , y , r );
Split( x , z , x , l-1 );
Revone( x );
Merge( x , z , x );
Merge( root , x , y );
}
void Revolve( int l , int r , int s )
{
int x,y,z,h;
Split( root , x , y , r-s );
Split( x , z , x , l-1 );
Split( y , y , h , s );
Merge( x , y , x );
Merge( x , z , x );
Merge( root , x , h );
}
void Insert( int k , int s )
{
int x,y;
Split( root , x , y , k );
Merge( x , x , s );
Merge( root , x , y );
}
void Delete( int s )
{
int x,y,z;
Split( root , x , y , s );
Split( x , x , z , s-1 );
Merge( root , x , y );
}
int Query( int l , int r )
{
int x,y,z,ans;
Split( root , x , y , r );
Split( x , z , x , l-1 );
ans = ftr[x].minx;
Merge( x , z , x );
Merge( root , x , y );
return ans;
}
int main()
{
for ( int n,m ; scanf ( "%d" , &n )==1 ; )
{
ftr[0].minx = inf;
sizes = root = 0;
for ( int i=1,x,t ; i<=n ; i++ )
{
scanf ( "%d" , &x );
Build ( t , x );
Merge ( root , root , t );
}
scanf ( "%d" , &m );
for ( int i=1 ; i<=m ; i++ )
{
char s[15];
int x,y,z;
scanf ( "%s" , s );
if ( s[0]=='A' )
{
scanf ( "%d%d%d" , &x , &y , &z );
Add( x , y , z );
}
else if ( s[0]=='M' )
{
scanf ( "%d%d" , &x , &y );
printf ( "%d\n" , Query( x , y ) );
}
else if ( s[0]=='R'&&s[3]=='E' )
{
scanf ( "%d%d" , &x , &y );
Reverse ( x , y );
}
else if ( s[0]=='R'&&s[3]=='O' )
{
scanf ( "%d%d%d" , &x , &y , &z );
Revolve ( x , y , z%(y-x+1) );
}
else if ( s[0]=='I' )
{
scanf ( "%d%d" , &x , &y );
Build ( z , y );
Insert ( x , z );
}
else if ( s[0]=='D' )
{
scanf ( "%d" , &x );
Delete ( x );
}
}
}
return 0;
}