Json数据转java对象

目的：把一个json数据转成java对象

需要准备一个：fastJson.jar包

一个简单的对象

package test.domain;

public class User {
	private String name;
	private String age;
	public String getName() {
		return name;
	}
	public void setName(String name) {
		this.name = name;
	}
	public String getAge() {
		return age;
	}
	public void setAge(String age) {
		this.age = age;
	}
	@Override
	public String toString() {
		return "User [name=" + name + ", age=" + age + "]";
	}
	
	
	
	
}

测试

package test.test;

import java.util.Map;

import com.alibaba.fastjson.JSON;
import com.alibaba.fastjson.JSONObject;

import test.domain.User;

public class demo {
	
	public static void main(String[] args) {
		
//		String json = "{'name':'z3','age':'20'}";
//		User u =  JSON.parseObject(json,User.class);	
//		System.out.println(u);
		
		//转成map再从map中获取相对应得数据
//		String json_1 = "{'id':'1','user':{'name':'z3','age':'20'}}";
//		Map map = JSON.parseObject(json_1);	
//		String aa =  map.get("user").toString();
//		User u =  JSON.parseObject(aa,User.class);	
//		System.out.println(u);	
		
		//转成json对象再从map中获取相对应得数据
		String json_2 = "{'id':'1','user':{'name':'z3','age':'20'}}";
		JSONObject jsonObject = JSONObject.parseObject(json_2);
		String string = jsonObject.getString("user");	
		
		User u =  JSON.parseObject(string,User.class);	
		System.out.println(u);	
		
	}
}