如何得到连续序号

--SQL2000

 

--1

select number from master..spt_values where type='p' --0-255

 

--2
select top 10000 id=identity(int,1,1) into #t from sysobjects,syscolumns 

 

--SQL2005生成系列号（行号）两种方式 
--1.用CTE递归测试   
;WITH t AS    
(    
    SELECT 1 AS num   
    UNION ALL   
    SELECT num+1    
    FROM t   
    WHERE num<100000   
)   
SELECT * FROM t    
OPTION(MAXRECURSION 0) 
  
--2.用通过系统表生成行号测试   
SELECT TOP 100000 num=ROW_NUMBER()OVER(ORDER BY GETDATE())   
FROM syscolumns a,syscolumns b  

--3.生成一个数字表，效率非常高
create function dbo.fn_nums(@n as bigint) 
returns table
as
return 
  with 
    t1 as (select 1 as c union all select 1),
    t2 as (select 1 as c from t1 as a,t1 as b),
    t3 as (select 1 as c from t2 as a,t2 as b),
    t4 as (select 1 as c from t3 as a,t3 as b),
    t5 as (select 1 as c from t4 as a,t4 as b),
    t6 as (select 1 as c from t5 as a,t5 as b),
    t7 as (select row_number() over(order by c) as n from t6)
    select n from t7 where n<@n;
go
--测试

select * from dbo.fn_nums(1000)