点击返回键俩次退出一次Toast

@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {

    if (keyCode == KeyEvent.KEYCODE_BACK && event.getRepeatCount() == 0) {

        exit();
        return true;
    }
    return super.onKeyDown(keyCode, event);
}
private long mExitTime;
public void exit() {
    if ((System.currentTimeMillis() - mExitTime) > 2000) {
        Toast.makeText(MainActivity.this, "再按一次退出应用", Toast.LENGTH_SHORT).show();
        mExitTime = System.currentTimeMillis();
    } else {
        finish();
        System.exit(0);
    }
}

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转载自blog.csdn.net/qq_42046338/article/details/81025589