JAVA-根据文件名排序

JAVA中对文件名进行排序

/**
 * @author wzx
 * @time 2018/8/4
 */
public class FileSortTest {

    public static final String PATH = "D:\\tmp\\";

    public static void main(String[] args) {
        List<File> files = new ArrayList<File>();
        files.add(new File(PATH + "test4.jpg"));
        files.add(new File(PATH + "test1.jpg"));
        files.add(new File(PATH + "test5.jpg"));
        files.add(new File(PATH + "test2.jpg"));
        files.add(new File(PATH + "test6.jpg"));
        files.add(new File(PATH + "test3.jpg"));
        files = sortFileByName(files, "desc");
        for (File file : files) {
            System.out.println(file.getName());
        }
    }

    /**
     *
     * @param files
     * @param orderStr 排序:asc,des,不区分大小写
     * @return
     */
    public static List<File> sortFileByName(List<File> files, final String orderStr) {
        if (!orderStr.equalsIgnoreCase("asc") && orderStr.equalsIgnoreCase("desc")) {
            return files;
        }
        File[] files1 = files.toArray(new File[0]);
        Arrays.sort(files1, new Comparator<File>() {
            public int compare(File o1, File o2) {
                int n1 = extractNumber(o1.getName());
                int n2 = extractNumber(o2.getName());
                if(orderStr == null || orderStr.length() < 1 || orderStr.equalsIgnoreCase("asc")) {
                    return n1 - n2;
                } else {
                    //降序
                    return n2 - n1;
                }
            }
        });
        return new ArrayList<File>(Arrays.asList(files1));
    }

    private static int extractNumber(String name) {
        int i;
        try {
            String number = name.replaceAll("[^\\d]", "");
            i = Integer.parseInt(number);
        } catch (Exception e) {
            i = 0;
        }
        return i;
    }
}

输出结果:

test6.jpg
test5.jpg
test4.jpg
test3.jpg
test2.jpg
test1.jpg

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转载自blog.csdn.net/wang704987562/article/details/81409265