实现数字型字符串的加法运算
如输入字符串num1=”1234”, num2=”234”,输出”1468”;num1=”1234”, num2=”-234”,输出”1000”;可实现高精度运算
代码实现
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
void
reverseStr(char* str)
{
int ii = 0;
int len = strlen(str);
char temp;
for (ii = 0; ii < len/2; ii++)
{
temp = str[len-1-ii];
str[len-1-ii] = str[ii];
str[ii] = temp;
}
return;
}
void
delFirststzero(char* str)
{
int is_neg = 0;
int len = strlen(str);
char* p_str = str + len - 1;
int ii = len - 1;
reverseStr(str);
if (*p_str == '-')
{
*p_str = 0;
is_neg = 1;
p_str--;
ii--;
}
for (; ii > 0; ii--)
{
if (*p_str != '0')
{
if (is_neg)
{
*(p_str+1) = '-';
}
break;
}
*p_str = 0;
p_str--;
}
reverseStr(str);
return;
}
void
add(const char* num1, const char* num2, char* resault)
{
char* p_num1 = NULL;
char* p_num2 = NULL;
char* p_num1_temp = NULL;
char* p_num2_temp = NULL;
char* p_temp = NULL;
char* p_res = resault;
char temp;
int len1 = 0;
int len2 = 0;
int max_len = 0;
int ii = 0;
int cmp_flag = 0;
int res_neg = 0;
if (!num1 || !num2 || !resault)
{
return;
}
len1 = strlen(num1);
len2 = strlen(num2);
if (num1[0] == '-')
{
len1--;
}
if (num2[0] == '-')
{
len2--;
}
max_len = (len1 > len2) ? len1 : len2;
p_num1 = (char*)malloc((max_len + 1) * sizeof(char));
p_num2 = (char*)malloc((max_len + 1) * sizeof(char));
if (!p_num1 || !p_num2)
{
return;
}
p_num1_temp = p_num1;
p_num2_temp = p_num2;
memset(p_num1, 0, (max_len + 1) * sizeof(char));
memset(p_num2, 0, (max_len + 1) * sizeof(char));
memcpy(p_num1, (num1[0] == '-') ? num1 + 1 : num1, len1 * sizeof(char));
memcpy(p_num2, (num2[0] == '-') ? num2 + 1 : num2, len2 * sizeof(char));
reverseStr(p_num1);
reverseStr(p_num2);
ii = (len1 > len2) ? len2 : len1;
p_temp = (len1 > len2) ? (p_num2 + len2) : (p_num1 + len1);
while(ii < max_len)
{
*p_temp++ = '0';
ii++;
}
p_temp = NULL;
ii = 0;
if ((num1[0] != '-' && num2[0] != '-') || (num1[0] == '-' && num2[0] == '-'))
{
//do add
*p_res = '0';
while (ii < max_len)
{
temp = *p_res - '0';
temp += (*p_num1 - '0' + *p_num2 - '0');
*p_res++ = (temp % 10 + '0');
*p_res = temp / 10 + '0';
p_num1++;
p_num2++;
ii++;
}
if (num1[0] == '-' && num2[0] == '-')
{
if (*p_res > '0')
{
p_res++;
}
*p_res = '-';
}
}
else
{
//do decrease
if (len1 == len2)
{
cmp_flag = memcmp((num1[0] == '-') ? num1 + 1 : num1, (num2[0] == '-') ? num2 + 1 : num2, max_len * sizeof(char));
if ( cmp_flag == 0)
{
*p_res = '0';
return;
}
else if (cmp_flag > 0)
{
if (num1[0] == '-')
{
res_neg = 1;
}
}
else
{
if (num2[0] == '-')
{
res_neg = 1;
}
}
}
else if (len1 > len2)
{
cmp_flag = 1;//num1 > num2
if (num1[0] == '-')
{
res_neg = 1;
}
}
else
{
cmp_flag = -1;//num1 < num2
if (num2[0] == '-')
{
res_neg = 1;
}
}
ii = 0;
*p_res = '0';
while (ii < max_len)
{
temp = *p_res - '0';
if (cmp_flag > 0)
{
*p_res++ = ((*p_num1 >= *p_num2) ? (*p_num1 - *p_num2) : (*p_num1 + 10 - *p_num2)) + '0';
if (*p_num1 < *p_num2)
{
(*(p_num1+1))--;
}
p_num1++;
p_num2++;
}
else
{
*p_res++ = ((*p_num2 >= *p_num1) ? (*p_num2 - *p_num1) : (*p_num2 + 10 - *p_num1)) + '0';
if (*p_num2 < *p_num1)
{
(*(p_num2+1))--;
}
p_num1++;
p_num2++;
}
ii++;
}
if (res_neg)
{
*p_res = '-';
}
}
reverseStr(resault);
delFirststzero(resault);
free(p_num1_temp);
free(p_num2_temp);
return;
}
int main(int argc, const char* argv[])
{
char rlt[256] = {0};
if (argc < 2)
{
return -1;
}
add(argv[1], argv[2], rlt);
printf("%s\n", rlt);
return 0;
}